Question

X x cube + 13 x square + 32 X + 20 ka gunankhand

Answer 1

Explanation:

${x}^{3} + 13 {x}^{2} + 32x + 20$

Substitute x=> -1

${( - 1)}^{3} + 13 {( - 1)}^{2} + 32( - 1) + 20 =$

$- 1 + 13 - 32 + 20 = 0$

So (x+1) is a factor of the above polynomial.

(x+1)√x^3+13x^2+32x+20 | (x^2+12x+20)

-x^3-x^2

___________

12x^2+32x+20

-12x^2-12x

_____________

20x+20

-20x-20

__________

0

____

${x}^{3} + 13 {x}^{2} + 32x + 20 =$

$(x + 1)( {x}^{2} + 12x + 20) =$

$(x + 1)( {x}^{2} + 2x + 10x + 20) =$

$(x + 1)(x(x + 2) + 10(x + 2)) =$

$(x + 1)(x + 2)(x + 10)$

Hope it helps you.