А=(x:x is is a factor of 12};
B=(x:x is a factor of 18)then AnB= ?
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The given sets are:
A={x:x∈N}={1,2,3,4.....}
B={x:x=2n,n∈N}={2,4,6,8,10....}
C={x:x=2n−1,n∈N}={1,3,5,7,9.......}
D={x:x is a prime number}={2,3,5,7,11,13....}
∴ A∩B={1,2,3,4....}∩{2,4,6,8....}
={2,4,6,8....}
=B
Hence
A∩B=B
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