Question

x*x-(m +2)x +(m +5)=0 equal roots
Solve it

Answer 1

they have equal roots means D=0
b^2-4ac
-(m+2)^2-4×1×(m+5)=0
-(2+m)^2-4m-20=0
+4+m^2+4m-4m-20=0
m^2-16=0
m=+-4
please mark it as brainliest

Answer 2

Hey mate..

Here's your answer..

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$since \: roots \: are \: equal \:so \: discriminant \: is \: 0 \\ now \: b {}^{2} - 4ac = 0 \\ { - (m + 2)}^{2} - 4 \times 1 \times (m + 5) = 0 \\ {m}^{2} + 4 + 4m - 4m - 20 = 0 \\ m {}^{2} - 16 = 0 \\ \\ {m }^{2} = 16 \\ m = + - 4$
$if \: m = 4 \\ equation \: is \: {x}^{2} - 6x + 9 \\ {x}^{2} - 3x - 3x + 9 \\ x(x - 3) - 3(x - 3) \\ \: \: \\ \\ so \: x = 3$
$if \: m = - 4 \\ so \: equation \: is \: {x}^{2} + 2x + 1 \\ or \: {(x + 1)}^{2} \: \: so \: x = - 1$

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HOPE IT HELPS..

@Rêyaañ11