Question

ᴛʀᴏɢᴏɴᴏᴍᴇᴛʀʏ

ғɪɴᴅ ᴛʜᴇ ᴍᴀxɪᴍᴜᴍ ᴠᴀʟᴜᴇ ᴏғ ᴛʜᴇ ᴇxᴘʀᴇssɪᴏɴ? ​

Answer 1

Answer:

1. view the picture for the answer explain

Answer 2

Answer:

Since value of sine and cos varies from 0 to 1.

Therefore , the max value of sine and cos must be 1.

Now , putting the values

= 1/[(sin^2 A)+(3 sin A × cos A)+(5cos^2 A)]

= 1/{(1)^2 + (3 × 1 × 1) + (5 × (1)^2)}

= 1/{ 1 + 3 + 5}

= 1/9