x-=--x+ ++x - --x*2 if x = 6
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Explanation:
x = 3;
x = ++x + (++x);
++x would increase ‘x’ by one and use this value. If you add 1 to the current value of x, which is 3, then you have 4.
x = 4 + (++x);
++x would increase ‘x’ by one again and use (again) this value. If you add 1 to the current value of x, which is 4, then you have 5.
x = 4 + (5);
Sum the remainders, and the solution of your question would be:
x = 9.
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