Question

x^√x = (√x)^-x ,then x= ?​

Answer 1

ANSWER:-

x^x√x = [x√x]^x

Take a log on both sides

log [(x)^x√x] = log [(x√x)^x]

```````````````log a^n = n*log a```````````

x√x * log x= x * log [ x√x]

``````````````log a*b = log a + log b`````````

x√x * log x = x * [log x + 1/2 log x]

x√x * log x = x * (3/2) * log x

x * log x cancel on both sides

√x = 3/2

squaring on both sides

x =9/4