(xᵃ/xᵇ)ᵃ*(xᵇ/xᵃ)ᵃ*(xᵃ/xᵃ)ᵇ, Simplify it.
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Using laws of exponents we get,
x^(a2 + ab + ab)-(ab + a2 + ab)
That is x^0, which is 1.
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