x^x√x=(x√x)^x then x is
Answers
Answered by
19
x^x√x = x^(x^3/2)
now (x√x)^x = (x^3/2)^x = x^(3/2×x)
=> x^(x^3/2) = x^(3/2×x)
=> x^3/2 = 3/2×x
=> (x^3/2)/x = 3/2
=> x^(3/2 - 1) = 3/2
=> x^(1/2) = 3/2
now squaring both sides
=> x = (3/2)^2 = 9/4
now (x√x)^x = (x^3/2)^x = x^(3/2×x)
=> x^(x^3/2) = x^(3/2×x)
=> x^3/2 = 3/2×x
=> (x^3/2)/x = 3/2
=> x^(3/2 - 1) = 3/2
=> x^(1/2) = 3/2
now squaring both sides
=> x = (3/2)^2 = 9/4
gudulsarangiozq6gq:
plz me brainliest
Answered by
15
Given x^{x √x} = (x √x)^x
Take Logarithm on both sides and apply: Log yⁿ = n Log y.
{x √x} * Log x = x Log (x √x)
x³/² * Log x = x Log ( x³/² )
x¹/² * Log x = Log x³/²
= 3/2 * Log x
=> x¹/² = 3/2
x = (3/2)² = 9/4
Take Logarithm on both sides and apply: Log yⁿ = n Log y.
{x √x} * Log x = x Log (x √x)
x³/² * Log x = x Log ( x³/² )
x¹/² * Log x = Log x³/²
= 3/2 * Log x
=> x¹/² = 3/2
x = (3/2)² = 9/4
Similar questions
Computer Science,
8 months ago
Chemistry,
8 months ago
Math,
8 months ago
Geography,
1 year ago
Math,
1 year ago
CBSE BOARD X,
1 year ago
Sociology,
1 year ago
English,
1 year ago