x(x+y)^3-3x^2y(x+y)
factorise it
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Answer:
Step-by-step explanation:
Given : x(x+y) 3 −3x 2 y(x+y)
Taking x(x+y) as common in the given question,
we get, x(x+y)[(x+y) 2 −3xy]
We know that, (a+b) 2 =a 2 +b 2 +2ab
x(x+y) 3 −3x 2 y(x+y)=x(x+y)(x 2 +y 2 +2xy−3xy)
So we get,
x(x+y) 3 −3x 2 y(x+y)=x(x+y)(x 2 +y 2 −xy)
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Step-by-step explanation:
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