Question

x (x²-1) + 7 (x²-1) Factorise
Process: (x+7) (x²-1²)
(x+7) (x+1)(x-1) ans
can u explain there did the (x²-1) in the question gone
PLEASE EXPLAIN CLEARLY
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Answer 1

1. take (X^2 - 1 ) common
2. break (x^2- 1^2)
3. by using Identity a2 – b2= (a + b)(a – b)

Answer 2

Step-by-step explanation:

x(x^2-1)+7(x^2-1)

(x+7)(x^2-1)

x+7=0 or x^2-1=0

x=-7 x^2=1

√x^2=√1-------root square get cancel

x=1------------(√1=1)

$o the two values of "X" are -7 and 1......