Question

|X. X2. 1+x³|
|Y. Y². 1+y³| is equals to 0
|Z. Z². 1+z³|
Prove xyz is -1

Answer 1

Answer:

If x, y, z are different and Δ = |(x, x2, 1 + x3), (y, y2, 1 + y3), (z, z2, 1 + z3)| = 0 then show that 1 + xyz = 0 Read more on Sarthaks.com - https://www.sarthaks.com/497273/if-x-y-z-are-different-and-x-x-2-1-x-3-y-y-2-1-y-3-z-z-2-1-z-3-0-then-show-that-1-xyz-0

Answer 2

please refer to the attached document

hope it helps u

please folow me