Question

{x:x2 + 5x+6=0}
write into the roaster form​

Answer 1

$\large \underline{ \underline{ \sf \: Answer : \: \: \: }}$

$\to${-2 , -3}

$\large \underline{ \underline{ \sf \: Solution : \: \: \: }}$

By prime factorisation method :

$\sf \implies {x}^{2} + 5x + 6 = 0 \\ \\ \sf \implies</p><p> {x}^{2} + 3x + 2x + 6 = 0 \\ \\ \sf \implies</p><p>x(x + 3) + 2(x + 3) = 0 \\ \\ \sf \implies </p><p>(x + 2)(x + 3) = 0$

The given equation x² + 5x + 6 can be written as :

(x + 2)(x + 3) = 0 , i.e x = -2 , -3

$\therefore$The solution set of the given equation can be written in roaster form as {-2 , -3}

_________________

Set

Set is collection of well defined object or data

There are two methods of representing a set :

$\star$Roaster or tabular form

$\star$ Set builder form

Answer 2

Answer:

-2, -3

Step-by-step explanation:

x2+5x+6=0

x2+3x+2x+6=0

x(x+3) 2 (x+3)=0

(x+3) (x+2)=0

The given equation x2+5x+6=0 can be written as

(x+3) ( x+2) =0

x= -2, -3

Therefore, the solution set of the given equation can be written in foster form (-2, -3)