Question

x(x2 + y2 – z) + y(-x² - y² + z²) – z(x² + y² – 2²)​

Answer 1

Answer:

Here we are observing that the term (x², y², z²) is belonging in each term but which is the coefficient of 'y' has given -x²-y²+z² while first and third term are same with x and -z coefficient respectively.

So, the term which is the coefficient of y i.e.,

-x²-y²+z²……(1)(say)

Taking minus (-) common from (1), we see that

The term with y coefficient becomes -(x²+y²-z²)

Now we are easy to observe that all the term with x, y and -z coefficients are equal . So now we can extract the common term which is (x²+y²-z²)……….(2)

Taking common (x²+y²-z²) with the coefficients x, y and -z gives

The required answer is (x²+y²-z²)(x+y-z)…..(3)

Now if you want to cross-check it simply multiply the equation (3) and the above question, you will find them equal.

Thanks…

Step-by-step explanation:

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