Question

x-y–0 is a line:
А
Passing through origin
Passing through (1,-1)
© || to y axis
||to x axis​

Answer 1

Answer:

Equation of line perpendicular to 2x+y+6=0 and passes through origin is x−2y=0.

Now, the point of intersection of 2x+y+6=0 and x−2y=0 is (−512,−56).

Similarly, the point of intersection of x−2y=0 and 4x+2y−9=0 is (59,109).

Let the origin divide the line x−2y=0 in the ratio λ:1

Therefore, x=λ+159λ−512=0

⇒λ=912=34