x+y=0, -x+z=0 and -2x-2y-z=0, find value of x,y,z.
Answers
Answered by
1
given X+y=0
X=-y. (1)
given -x+z=0
z=X
z=-y. (2)
given -2x-2y-z=0
-2(-y)-2y-(-y)=0 from (1)&(2)
2y-2y+y=0
so y=0
by problem X+y=0
x+0=0
so X=0
by problem -x+z=0
-0+z=0
z=0
X=-y. (1)
given -x+z=0
z=X
z=-y. (2)
given -2x-2y-z=0
-2(-y)-2y-(-y)=0 from (1)&(2)
2y-2y+y=0
so y=0
by problem X+y=0
x+0=0
so X=0
by problem -x+z=0
-0+z=0
z=0
lalitbhatt125:
bUt bro the ans. is x=1, y=-1, z=1 give stepwise solution...
Answered by
2
hello
x+y=0
y=0-x
y= -x
-x+z=0
z=0+x
z=x
-2x-2y-z=0
putting the value in the equation
-2x-2(-x)-x=0
-2x+2x-x=0
-x=0
x=0
then,
x+y=0
0+y=0
y=0
-x+z=0
0+z =0
z=0
hope this answers will help you
Similar questions