Question

x-y+1=0 , 3x+2y-12=0 solve by elimination method​

Answer 1

From eq1 we get

x=-1+y

putting the value of x in eq 2 we get

3(-1+y)+2y=12

-3+3y+2y=12

5y=12+3

y=15/5=3

put the y=3 in eq 1we get

x-3+1=0

x-4=0

x=4

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Answer 2

Answer:

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