Question

x-y+1=0 and 3x+2y-12=0

Answer 1

$\huge \bf{HEY \: FRIENDS!!}$


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$\huge \bf \underline{Here \: is \: your \: answer↓}$


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▶⏩ Solve these equations:-)


$\bf{x - y + 1 = 0.}$

$\bf{=> x - y = -1..............(1).}$


$\bf{3x + 2y - 12= 0.}$

$\bf {=> 3x + 2y = 12...............(2).}$



$\boxed{Solving \: by \: elimination \: method}$

↪➡ Multiply equation (1) by 3.


$\bf{=> 3x - 3y = -3...........(3).}$

▶⏩ Now, Substract in equation (2) and (3).


3x + 2y = 12.
3x - 3y = -3.
(-)...(+)......(+).
__________
=> 5y = 15.

$\huge\bf{=> y = 3.}$

↪➡ Put the value of ‘ y’ in equation (1).

=> x - 3 = -1.

=> x = -1 + 3.

$\huge \bf{=> x = 2.}$


✅✅ Hence, it is solved ✔✔.


$\huge \boxed{THANKS}$



$\huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}$

Answer 2

$\huge \bf{hey}$

$\huge \underline{here \: is \: the \: answer}$
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$\bf{x - y + 1 = 0 \: and \: 3x + 2y - 12 = 0}$

$\bf{x - y + 1 = 0}$


$\bf{x - y = - 1....(1)}$



$\bf{and}$


$\bf{3x + 2y - 12 = 0}$

$\bf{3x + 2y = 12}$


$\boxed{multiply \: 1in \: equation \: 2 and \: 3in \: equation \: 1}$
$\bf{3x - 3y + 3 = 0}$


$\bf{3x - 3y = - 3....(3)}$



$\bf{3x + 2y - 12 = 0}$




$\bf{3x + 2y = 12......(4)}$


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elimination method will used here see in pic

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$\bf{ \: hence \: y = 3}$


$\boxed{put \: value \: of \: y \: in \: equation \: (1)}$


$\bf{x - y = - 1}$

$\bf{x - 3 = - 1}$

$\bf{x = - 1 + 3}$
$\bf{hence \: x = 2}$

$\huge{hope \: it \: helps}$



$\huge{thanks}$