x+y+1=0,x=5 find the angle between lines
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Heya user,
Clearly, point of intersection would be -->
x = 5; y = -6 .'. Point is ( 5 , -6 );
Now, take any point on Equation x + y = -1, say when y = -5;
Then the point is --> ( 4 , -5 );
The slope is --> [ -5 - (-6) ] / [ 4 - 5 ] = -1 ..
And hence, tan θ = -1 , which gives, θ = tan⁻¹ -1 = π/4
And hence, the angle is π/4
Clearly, point of intersection would be -->
x = 5; y = -6 .'. Point is ( 5 , -6 );
Now, take any point on Equation x + y = -1, say when y = -5;
Then the point is --> ( 4 , -5 );
The slope is --> [ -5 - (-6) ] / [ 4 - 5 ] = -1 ..
And hence, tan θ = -1 , which gives, θ = tan⁻¹ -1 = π/4
And hence, the angle is π/4
Anonymous:
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aaa i did not getting the answer
You can find that on google though
ok
thank u
See........ Just write whatever I have written, in your copy, and you'll get why I've written that
ok
ur name pls
Yuichiro
oh thanks yuichiro
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