x + y - 1 = 0Find three solutions for the given equation.
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Answer :
The given equation is
x + y - 1 = 0 ...(i)
a)
Putting x = 0 in (i), we get
0 + y - 1 = 0
or, y = 1
Thus, a solution be x = 0, y = 1
b)
Putting x = 1/2 in (i), we get
1/2 + y - 1 = 0
or, y = 1/2
Thus, a solution be x = 1/2, y = 1/2
c)
Putting y = 0 in (i), we get
x + 0 - 1 = 0
or, x = 1
Thus, a solution be x = 1, y = 0
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Answered by
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Hi ,
It is given that ,
x + y - 1 = 0
=> y = 1 - x
_________________________
x | y = 1 - x | ( x , y )
_________________________
0 | y= 1 -0 = 1 | ( 0 , 1 )
_________________________
1 | y = 1-1 = 0 | ( 1 , 0 )
_________________________
3 | y = 1 - 3 = -2 | ( 3 , - 2 )
_________________________
Therefore ,
( 0 , 1 ) , ( 1 , 0 ) and ( 3 , -2 ) are
three solutions of the given
linear equation .
I hope this helps you.
: )
It is given that ,
x + y - 1 = 0
=> y = 1 - x
_________________________
x | y = 1 - x | ( x , y )
_________________________
0 | y= 1 -0 = 1 | ( 0 , 1 )
_________________________
1 | y = 1-1 = 0 | ( 1 , 0 )
_________________________
3 | y = 1 - 3 = -2 | ( 3 , - 2 )
_________________________
Therefore ,
( 0 , 1 ) , ( 1 , 0 ) and ( 3 , -2 ) are
three solutions of the given
linear equation .
I hope this helps you.
: )
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