x + y = 1; 2x + 3y = 0 Solve the same equation by the graph
Answers
Answer:
(3,-2) x=3 and y= -2
Step-by-step explanation:
[equation 1]
x + y = 1
⇒x/1 + y/1 = 1
intercept form: plot denominator of x (1) on x-axis and denominator of y (1) on y-axis join the two points and you got your first equation plotted
now for
[equation 2]
2x + 3y =0
⇒3y = -2x
⇒y= (-2/3) x
plot a line passing through origin and making an angle of tan^-1(-2/3) [inverse tangent function] with the x-axis
you got your second equation plotted.
the point where these two lines inersect (meet) is the solution
ELIMINATION METHOD;
x + y = 1 _____(i) × 2
2x + 3y = 0 ___(ii) × 1
2x + 2y = 2
±2x ± 3y = ±0
----------------------
-y = 2
y = -2
Putting value of y in (i) equation;
x + (-2) = 1
x = 1 + 2
x = 3
GRAPHICAL METHOD;
For (i) equation;
x - 0 1
y - 1 0
For (ii) equation;
x - 3 (-3)
y - (-2) 2
Plot the values of x and y of both equations on the graph and you will obtain the value of x = 3 and y = (-2).