Math, asked by ddmuzalde, 11 months ago

x + y = 1; 2x + 3y = 0 Solve the same equation by the graph

Answers

Answered by krustyKrabbs
0

Answer:

(3,-2)      x=3 and y= -2

Step-by-step explanation:

[equation 1]

  x + y = 1

⇒x/1  + y/1 = 1

intercept form: plot denominator of x (1) on x-axis and denominator of y (1)  on y-axis join the two points and you got your first equation plotted

now for

[equation 2]

2x + 3y =0

⇒3y = -2x

⇒y= (-2/3) x

plot a line passing through origin and making an angle of tan^-1(-2/3) [inverse tangent function] with the x-axis

you got your second equation plotted.

the point where these two lines inersect (meet) is the solution

Answered by anshikaverma29
0

ELIMINATION METHOD;

x + y  = 1 _____(i) × 2

2x + 3y = 0 ___(ii) × 1

 2x + 2y = 2

±2x ± 3y = ±0

----------------------

         -y = 2

         y = -2

Putting value of y in (i) equation;

x + (-2) = 1

x = 1 + 2

x = 3

GRAPHICAL METHOD;

For (i) equation;

x -  0    1

y -  1     0

For (ii) equation;

x -   3      (-3)

y -  (-2)     2

Plot the values of x and y of both equations on the graph and you will obtain the value of x = 3 and y = (-2).

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