Question

x-y=1 xy=6 find the value of x^2+y^2​

Answer 1

Answer:

Answer

x−y=−6,xy=4

(x−y)3=x3−y3−3x2y+3xy2=−216

=x3−y3−3yx(x−y)=−216

x3−y3=−216+3(4)(−6)

x3−y3=−288

Step-by-step explanation:

SAME SUM

JUST change the numbers

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