Question

X+y =10 and x-y=6 what is the value ofx^3-y^3

Answer 1

Answer:

The value of $x^3-y^3$ is 1216.

Step-by-step explanation:

Given-  

$x+y =10 \\ x-y=6$

To find-

The value of $x^3-y^3$

Solution-

$x+y =10 \:\:\:\:\:\:\:\:\: (1)\\ x-y=6 \:\:\:\:\:\:\:\:\: (2)$

By Adding equation (1) and (2)

Y get cancel

$x=16$

Put the value of x in equation (1)

$16+y=10\\y= 10-16$

$y=-6$

Now, We find the value of

$x^{3} = 10^{3}= 1000\\ y^{3} = (-6)^{3}=-216$ (Cube of Negative number is always negative.)

The value of $x^3-y^3$  = $1000-(-216)$

BY multiplying two negative sign we get positive sign.

The value of $x^3-y^3$  =  $1000+216$

The value of $x^3-y^3$  = $1216$

∴ The value of $x^3-y^3$ is 1216.