√x+√y=√10 dy/dx please find the derivative of the function
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to differentiate wet x √x + √y = √10
√y = √10 - √x
1/(2√y) dy/dx = 0 - 1/(2√x)
=> dy/dx = - 2√y×1/2√x
=> dy/dy = - √y/√x
=> dy/dx = - (√10 - √x)/√x
=> dy/dx = (√x - √10)/√x
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