Math, asked by rawatdiya235, 5 hours ago

X+y=11, 2x+3y=26 substituition method

Answers

Answered by chanchalmaravithb
0

Answer:

STEPS USING SUBSTITUTION

{

x+y=11

2x+3y=26

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

x+y=11,2x+3y=26

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

x+y=11

Subtract y from both sides of the equation.

x=−y+11

Substitute −y+11 for x in the other equation, 2x+3y=26.

2(−y+11)+3y=26

Multiply 2 times −y+11.

−2y+22+3y=26

Add −2y to 3y.

y+22=26

Subtract 22 from both sides of the equation.

y=4

Substitute 4 for y in x=−y+11. Because the resulting equation contains only one variable, you can solve for x directly.

x=−4+11

Add 11 to −4.

x=7

The system is now solved.

x=7,y=4

Answered by arepallysurya
0

Answer:

1) x+y = 11

x = 11 -y → eq 1

2) 2x + 3y = 26 → eq 2

Step-by-step explanation:

substituting eq 1 in eq 2 we get :

2 ( 11- y) + 3y = 26

22- 2y + 3y = 26

22 + y = 26 → y = 4

substituting y = 4 in eq 1 we get

x+y = 11 , x+4 = 11

x = 11- 4 , x = 7

therefore , x = 7 ; y = 4

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