Question

x-y=12 and xy=25/4, find x+y​

Answer 1

Answer:

hey mate here is your answer

Step-by-step explanation:

$x - y = 12$

multiplying this equation by y

$xy - {y}^{2} = 12y$

$x y= \frac{25}{4}$

putting value of xy in the first equation

$\frac{25}{4} - {y}^{2} = 12y$

$25 - 4 {y}^{2} = 12y \times 4$

$4 {y}^{2} + 48y - 25 = 0$

$(2y+ 25)(2y - 1) = 0$

hence values of y are -25/2 and 1/2

here the value of y will be -25/2

putting value of y in xy=25/4

therefore value of x will be -1/2

hope this helps you.......

Answer 2

Answer:

pl see below:

Step-by-step explanation:

$(a + b)^{2} = (a- b)^{2} + 4ab$

so,

(x+y) ^2=(x-y)^2+4xy

=12^2 +4*(25/4)

=144+25

=169

x+y=+/- √169

=+/-13 Ans.

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