x-y=12 and xy=25÷4,findx+y
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Answer:
+13 or -13
Step-by-step explanation:
x-y = 12
then, x = 12+y
putting this value of x in xy = 25/4
we get, (12+y)y = 25/4
=> 12y+y^2 = 25/4
=> 4y^2 + 48y = 25
=> 4y^2 + 48y - 25 = 0 [ multiplying all by 4]
=> 4y^2 + 50y - 2y - 25 = 0
=> 2y (2y-1) +25 (2y-1) = 0
=> (2y-1) (2y+25) = 0
=> y = 1/2 or y = -25/2
for y =1/2
then x = 12+1/2 = 25/2
x+y = 25/2+1/2 = 26/2 === 13
or
for y = -25/2
then x = -1/2
So, x+y = -1/2 - 25/2 ===== -13
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