Question

x+y=12 and xy=32,find the value of x²+y²

Answer 1

From the Question,

$\sf{x + y = 12 \: and \: xy = 32}$

★Recall the identity,

(a+b)² = a²+2ab+b²

To find the value of x² + y²

Now,

x² + y²

Adding and Subtracting 2xy,

»(x²+y²+2xy) - 2xy

»(x+y)² -2xy

»(12)² -2(32)

»144-64

»80

Thus,x²+y² is equal to 80

Answer 2

Answer:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$