Question

x+y =12 and xy = 32 find the value of xsuare = y square

Answer 1

Given that: x+y=12 and xy = 32

Using the identity, (x+y)

2 = x

2 +2xy+y 2⇒ (12) 2=x

2 +64+y

2⇒ 144 = x 2 +y 2+64⇒ 144−64 = x+y 2⇒ 80 = x 2 +y 2

The answer is x 2 +y 2

= 80

hope it helps you.

Answer 2

Answer:

X + y = 12 1st equation

xy = 32 2nd equation

X = 12 - y

put the value of X in 2nd equation

xy = 32

(12 - y) y = 32

12y - y^2 - 32

y^2 - 12y + 32

y^2 - 8y - 4y + 32

y ( y -8). -4 ( y -8)

(y-4). (y - 8)

y = 4

y = 8

X+ y = 12

X + 8 = 12

X = 12- 8

X = 4

X square = 4× 4 = 16

y square = 8 × 8 = 64

Step-by-step explanation:

plz mark me as brainlist