Question

x+y=12 and xy=32 find x^2+y^2

Answer 1

x + y = 12

x*y = 32

on solving

x = 8 , y = 4

= x^2 + y ^2

= 8^2 + 4^2

= 64 + 16

= 80

Hope it helped you.....

Answer 2

$\huge\mathfrak{Heya}$

$\mathsf{Given \ :-}$

$\mathsf{x + y \ = \ 12}$

$\mathsf{And}$

$\mathsf{xy \ = \ 32}$

$\mathsf{To \ find \ :-}$

$\mathsf{x^2 + y^2 \ = \ ? }$

$\mathsf{Solution \ :-}$

$\mathsf{Using \ formula}$

$\mathsf{(x + y) ^2 \ = \ x^2 + y^2 + 2xy}$

$\mathsf{Putting \ values.}$

$\mathsf{We \ get,}$

$\mathsf{(12)^2 \ = \ x^2 + y^2 + 2×32}$

$\mathsf{x^2 + y^2 \ = \ 144 - 64}$

$\mathsf{x^2 + y^2 \ = \ 80}$

$\huge\mathbb{Hope \ this \ helps.}$