X+y=12, xy=27 find x^3+y^3
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Given:-
x + y = 12
xy=27
To find:-
x³+y³
Solution:-
We know that,
(a+b)³=a³+b³+3ab(a+b)
Hence,
(x+y)³ = x³+y³+3xy(x+y)
Substituting the values of x+y and xy , we get
(12)³= x³+y³+3(27)(12)
1728 = x³+y³+972
→ x³+y³=1728-972
→ x³+y³=756
Hence, solved.
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