Question

x+y= 12,xy=32,find the value of x²+y²​

Answer 1

Answer:

$\tt \longrightarrow\tt \: (x + y) ^{2} = {x}^{2} + 2xy + {y}^{2} \\ \tt \longrightarrow (12) ^{2} + {x}^{2} + 2 \times 32 + {y}^{2} \\ \tt \longrightarrow \: {x ^{2} } + {y}^{2} = 144 - 64 = 80$

Leave A Thanks(heart) for answer.