x+y=√13,x-y=√5 then xy=?
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Answered by
1
Answer:
x+y = √13
x-y = √5
x = (√13+√5)/2
y = (√13-√5)/2
xy = (13-5)/4 = 8/4 = 2
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Answered by
0
Answer:
4.5
Explanation step by step:
x+y=√13
squaring on both sides
(x+y)^2=13
x-y=√5
squaring on both sides
(x-y)^2=5
expand using their respective formulae
x^2+y^2+2xy=13-->eq1
x^2+y^2-2xy=5-->eq2
substract eq2 from eq1
WE get
4xy =18
xy=18/4
xy =4.5
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