x+y=16,
x-y=4 find the solution of the following pair of linear equation
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X = 10 AND Y = 6
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Answer:
x = 10
y = 6
Step-by-step explanation:
This can be solved using various ways
1) Trial and Error Method
RHS = 16 ; 4
LHS = x + y ; x - y
let x be 1, y be 15
x+y = 1+15 = 16
x - y = 1 - 15 = -14
LHS ≠ RHS
let x be 9, y be 5
x - y = 9 - 5 = 4
x + y = 9 + 5 = 14
LHS ≠ RHS
let x be 10, y be 6
x + y = 10 + 6 = 16
x - y = 10 - 6 = 4
LHS = RHS
2) By adding both the equation
(x + y) + (x - y) = 16 + (4)
2x = 20
x = 10
y = 16 - x = 16 - 10 = 6
x = 10
y = 6
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