Question

x+y=16'x-y=4Find the solution of the following pair of linear equations

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Answer 1

x + y = 16

x - y = 4

Add both equations

2x = 20

x = 10

Put value of x in any one of the equation

10 + y = 16

y = 6

Therefore the values of x and y are 10 and 6 respectively.

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Answer 2

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$\mathtt{\huge{\underline{\red{Answer\: :}}}}$

$\: \large \orange{ \bold{ \underline{step \: by \: step \: explaination : }}}$

$\green{\bf{Given}} \begin{cases} \sf{x+y=16 ...(1)} \\ \sf{x-y=4 .....(2)} \\ \rm{Find \: the \: solution \: of \:following \:pairs } \end{cases}$

$\: \qquad \bf{x + y = 16} \: \: \: \: \: ......eqn(1)$

$\: \qquad \bf \: x - y = 4 \: \: \: \: ......eqn(2)$

$\: \: \quad \implies \sf{2x = 20}$

$\: \quad \implies \sf{x = 10}$

• Put the value of X in equation (1)

$\: \quad \implies \bf \: \: x + y = 16$

$\: \quad \implies \sf \: 10 + y = 16$

$\: \quad \implies \sf \: y = 16 - 10$

$\: \quad \implies \sf \: y = 6$

$\: \sf \large \boxed{ \bf{ \underline{the \: solution \: of \: this \: linear \: equation \: is \: x = 10 \: and \: y = 6}}}$