Question

x+y=17 and xy=25,x>y than (x3-y3) ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

We know: a³-b³=(a-b)(a²+b²+ab)

So, We need to find the value of (x-y) and (x²+y²).

Step-by-step explanation:

step-1: Find the value of (x²+y²);

x+y=17..........(given)

=>(x+y)²=289

=>x²+y²+2xy=289

=>x²+y²+2*25=289............(xy=25, given)

=>x²+y²=289-50

=>x²+y²=239

Step-2: Find the value of (x-y);

(x-y)²=x²+y²-2xy

=>(x-y)²=239-2*25

=>(x-y)²=189

=>x-y=3✓21

Final step: putting the value of (x-y) and (x²+y²)

x³-y³=(x-y)(x²+y²+xy)

x³-y³=(3✓21)(239+25)

x³-y³=(3✓21)*(264)

x³-y³=792✓21