Question

(√x+√y)²= __________​

Answer 1

$\huge\underline\bold\pink{Answer}$

$( \sqrt{x} + \sqrt{y} )^{2} \\ \\ = { \sqrt{x} }^{2} + 2 \times \sqrt{x} \times \sqrt{y} + { \sqrt{y} }^{2} \\ = x + 2 \sqrt{xy} + y \\ = x + y + 2 \sqrt{xy}$

Hope this helps you ^_^

Answer 2

Answer:

x+y+2$\sqrt{xy}$

Step-by-step explanation:

Due to the formula : $(a+b)^{2}$ = $a^{2}$+$b^{2}$+2ab

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