Question

x/y=(2/3) ^-2×(3/5) ^-2, find(y/x) ^-1​

Answer 1

Answer:

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Given,x2=21

So, x=4

Also given yx=32

⇒3×x=2×y

⇒3×(4)=2×y

⇒y=6

Answer 2

Answer:

Value of

$(\frac{x}{y}) - 2$

Value of

$( \frac{x}{y}) \\ = ( \frac{2}{3} ) \div ( \frac{3}{5}) - 2( \frac{x}{y} ) - 2 \\ = (\frac{ - 2}{3}) \times 3 \div (\frac{3}{5}) - 2 - 2 \\ = (\frac{ - 22}{3})$

Value of

$( \frac{x}{y}+ \frac{y}{x}) - 1 \\ = (( \frac{ - 2}{3} )3 \div ( \frac{3}{5} ) - 2) + (( \frac{ - 3}{2} ) \frac{1}{3} \div ( \frac{5}{3}) - 2 - 1 \\ = ( \frac{ - 16}{3}) + ( \frac{ - 23}{10} ) - 1$

Hope this helps please follow

Value of

$( \frac{x}{y} + \frac{y}{x} ) - 1$