Question

(x + y)2 – 3x – 3y + 2​

Answer 1

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• Factorise ${(x + y)}^{2} - 3x - 3y + 2$

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${(x + y)}^{2} - 3x - 3y + 2$

$= {(x + y)}^{2} - 3(x + y) + 2$

$= {(x + y)}^{2} - (x + y) - 2(x + y)+ 2$

$= (x + y)(x + y - 1) -2 (x + y - 1)$

$= (x + y - 2)(x + y - 1)$

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• $(x + y - 2)(x + y - 1)$

Answer 2

Step-by-step explanation:

$x {}^{2} + y {}^{2} + 2xy - 3x - 3y + 2$