Question

(x-y)2-3x+ 3y factorise it ​

Answer 1

Answer:

Now,

(x+y)

2

−3x−3y+2

=(x+y)

2

−3(x+y)+2

=(x+y)

2

−(x+y)−2(x+y)+2

=(x+y)(x+y−1)−2(x+y−1)

=(x+y−1)(x+y−2),

whichistherequired

factorization.

Answer 2

Answer:

$\bf\blue{(x - y)2 - 3x + 3y}$

Solution:

$= (x + y)2 - 3(x + y) + 2 \\ \\ = (x + y) - 2(x + y) - 2(x + y) + 2$

$= (x + y)(x + y - 1) - 2(x + y - 1) \\ \\ = (x + y - 1)(x + y - 2)$

Hope it will be helpful :).....✍️