Math, asked by md8241309, 5 days ago

x+y/2+3x-5y/4=2
x/14+y/18=1​

Answers

Answered by mrstark94
0

Step-by-step explanation:

Hence the solution of the linear equation is x = 7 and y = 9.

Attachments:
Answered by karmaan958
1

x + y/2 + 3x - 5y/4 = 2

= 4x + 2y + 12x - 5y = 8

= 16x - 3y = 8 (eqn. no. 1)

x/14 + y/18 = 1

= 9x + 7y = 126 (eqn. no. 2)

Now, eliminate x or y by equating their values

Here, I'm going to eliminate y.

multiplying eqn. no. 1 by 7

16x - 3y = 8

7(16x - 3y = 8)

= 112x - 21y = 56 (eqn. no. 3)

multiplying eqn. no. 2 by 3

9x + 7y = 126

3(9x + 7y = 126)

= 27x + 21y = 378 (eqn. no. 4)

Now, the values of y is same in both the equations.

Eliminate y by adding eqn. no. 3 to eqn. no. 4

(112x - 21y = 56) + (27x + 21y = 378)

112x + 27x - 21y + 21y = 56 + 378

139x = 434

x = 434/139

putting the value of x in the eqn. no. 1

16x - 3y = 8

16(434/139) - 3y = 8

6944/139 - 3y = 8

6944 - 417y = 1112

- 417y = 1112 - 6944

- 417y = - 5832

y = (-5832/-417)

y = 1944/139

Hence, x = 434/139 & y = 1944/139

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