x+y/2+3x-5y/4=2
x/14+y/18=1
Answers
Step-by-step explanation:
Hence the solution of the linear equation is x = 7 and y = 9.
x + y/2 + 3x - 5y/4 = 2
= 4x + 2y + 12x - 5y = 8
= 16x - 3y = 8 (eqn. no. 1)
x/14 + y/18 = 1
= 9x + 7y = 126 (eqn. no. 2)
Now, eliminate x or y by equating their values
Here, I'm going to eliminate y.
multiplying eqn. no. 1 by 7
16x - 3y = 8
7(16x - 3y = 8)
= 112x - 21y = 56 (eqn. no. 3)
multiplying eqn. no. 2 by 3
9x + 7y = 126
3(9x + 7y = 126)
= 27x + 21y = 378 (eqn. no. 4)
Now, the values of y is same in both the equations.
Eliminate y by adding eqn. no. 3 to eqn. no. 4
(112x - 21y = 56) + (27x + 21y = 378)
112x + 27x - 21y + 21y = 56 + 378
139x = 434
x = 434/139
putting the value of x in the eqn. no. 1
16x - 3y = 8
16(434/139) - 3y = 8
6944/139 - 3y = 8
6944 - 417y = 1112
- 417y = 1112 - 6944
- 417y = - 5832
y = (-5832/-417)
y = 1944/139
Hence, x = 434/139 & y = 1944/139