Question

(x+y)²- (a+b)²
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Answer 1

Since

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

So,

$= (x+y)² \: - (a+b)² \\ = {x}^{2} + {y}^{2} + 2xy - ( {a}^{2} + {b}^{2} + 2ab) \\ = {x}^{2} + {y}^{2} + 2xy - {a}^{2} + - {b}^{2} - 2ab$

hope it will help u ✨☺️

Answer 2

Answer:

$(x+y)^{2} - (a+b)^{2}$

                $(x+y)^2=x^2+2xy+y^2$

                $(a+b)^2=a^2+2ab+b^2$

$(x^2+2xy+y^2)-(a^2+2ab+b^2)$

$x^2+2xy+y^2-a^2-2ab-b^2$