Question

x+y= -2 by graphical method table​

Answer 1

${\large{\pmb{\sf{\underline{Required \: Solution...}}}}}$

It is given that we have to show the following equation by graphical method table: x + y = -2

Firstly let us put x = 0 in equation

⇒ x + y = -2

⇒ 0 + y = -2

⇒ y = -2

⇒ The value of y we get -2

⇒ The coordinates are (0,-2)

Now let us put y = 0 in equation

⇒ x + y = -2

⇒ x + 0 = -2

⇒ x = -2

⇒ The value of x we get -2

⇒ The coordinates are (-2,0)

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c}\sf \red{x} & \sf -2 & \sf 0 \\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{} &\frac{\qquad \qquad \qquad \qquad}{}\\ \sf \red{y} & \sf 0 & \sf -2\end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

Kindly refer to attachment 1st for the graph related to this question.

${\large{\pmb{\sf{\underline{Additional \: information...}}}}}$

The system used for describing the position of a point in the plane is known as cartesian system.

Relation between the signs of the coordinates of a point and the quadrant of a point in which it lie.

1) If the point is in the first quadrant then the point will be in the form of (+,+) since the 1st quadrant is enclosed by the positive x-axis and positive y-axis

2) If the point is in the second quadrant then the point will be in the form of (-,+) since the 2nd quadrant is enclosed by the negative x-axis and positive y-axis

3) If the point is in the third quadrant then the point will be in the form of (-,-) since the 3rd quadrant is enclosed by the negative x-axis and negative y-axis

4) If the point is in the fourth quadrant then the point will be in the form of (+,-) since the 4th quadrant is enclosed by the positive x-axis and negative y-axis

Kindly refer to attachment 2nd for understanding this concept.