Question

x-y=2 then x3-y3-6xy

Answer 1

x-y=2
x=2+y
-y=2-x
y=-2+x


x3-y3-6xy. [x3-y3= (x-y)(x^2+xy+y^2)]
step:1 :: (x-y)(x^2+xy+y^2)] - 6xy

step:2:: { (2) [(2+y)^2+(2+y)(-2+x) + (-2+x)^2] } - [ (6) (2+y)(-2+x )]

step:3:: { [2] [ (4+4y+y^2)] + [(-4+2x-2y+xy) + [x^2+4x+4] } -[6 (-4+2x-2y+xy)]

step:4:: [(2)(4+4y+y^2-4+2x-2y+xy+x^2+4x+4)] + [24-12x+12y-6xy]

step:5:: [(2) (x^2+y^2+6x+2y+xy+4)] + [24-12x+12y-6xy]

step:6:: (2x^2 + 2y^2 + 12x + 4y + 2xy + 8)+ (24-12x+12y-6xy)

step:7:: (2x^2 + 2y^2 + 16y - 4xy + 32)

I hope it is helpful to you......

Answer 2

If x-y=2 ,what is x3-y3-6xy