Question

(√x+√y)^2+(√x-√y)^2
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please....​

Answer 1

Answer:

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Step-by-step explanation:

Given : X+\sqrt{x^2-y^2}X+

x

2

−y

2

To find : The squire root of X+\sqrt{x^2-y^2}X+

x

2

−y

2

.

Step-by-step explanation:

At first let squire root of X+\sqrt{x^2-y^2}X+

x

2

−y

2

is II , that is,

I=\sqrt{ X+\sqrt{x^2-y^2}}\hfill (1)I=

X+

x

2

−y

2

\hfill(1)

Since both terms x and y in the root \sqrt{x^2-y^2}

x

2

−y

2

are perfect squires we can apply difference of squire formula to factor it.

That is,

x^2-y^2=(x+y)(x-y)x

2

−y

2

=(x+y)(x−y)

Substitute this value in (1) we get,

\therefore I=\sqrt{X+\sqrt{(x+y)(x-y)}}∴I=

X+

(x+y)(x−y)

which is the required solution.