Question

(x+y)^2-(x-y)^2 please solve​

Answer 1

Answer:

Question:-

$\mathtt{ = {(x + y)}^{2} - {(x - y)}^{2} }$

Formula used:-

We solve this question with the below formula:-

$\mathtt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} }$

$\mathtt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} }$

Solution:-

$\mathtt{ = {(x + y)}^{2} - {(x - y)}^{2} }$

$\mathtt{ = {x}^{2} + 2xy + {y}^{2} - ( {x}^{2} - 2xy + {y}^{2}) }$

$\mathtt{ = {x}^{2} + 2xy + {y}^{2} - {x}^{2} + 2xy - {y}^{2} }$

$\mathtt{ = 2xy + 2xy}$

$\mathtt{ = 4xy}$

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess

Answer 2

Question:-

$(x + y) { }^{2} - {(x - y)}^{2}$

Step-by-step explanation:

ᴛʜɪs ɪs ɪɴ ғʀᴏᴍ ᴏғ.

a²- b² = (a + b) (a- b)

ᴛʜᴜs ,

( x + y ) ²- (x-y) ²

= ( x + y + x - y ) ( x+y - x + y )

= 2x X 2y

= 4xy

answer

( x + y ) ²- (x - y) ² = 4xy