Question

(x+y)²-(x-y)²/x²y-xy²​

Answer 1

Answer:

4/x-y

Step-by-step explanation:

$({x + y})^{2} - ({x - y})^{2} \div {x}^{2}y - x {y}^{2}$

${x}^{2} + {y}^{2} + 2xy - ( {x}^{2} + {y}^{2} - 2xy) \div {x}^{2} y - x {y}^{2}$

${x}^{2} + {y}^{2} + 2xy - {x}^{2} - {y}^{2} + 2xy \div {x}^{2} y - x {y}^{2}$

then cancelling +ve ,-ve x sq. and y sq.

$2xy + 2xy \div {x}^{2} y - x {y}^{2}$

$4xy \div {x}^{2} y - x {y}^{2}$

after taking common xy(x-y)in denominator and then cancelling xy from numerator and denominator...

$4 \div (x - y)$

{let me know if it's correct.. hope it helps}