Question

x+y/2-x-y/3=8 & x+y/3+x-y/4=11 method of elimination how to solve

Answer 1

x=167 and y=-23................

Answer 2

Answer:

(15,-27)

Step-by-step explanation:

Equation 1 : $\frac{x+y}{2}-\frac{x-y}{3}=8$

$\frac{3x+3y+2x-2y}{6}=8$

$\frac{5x+y}{6}=8$

$5x+y=48$--------A

Equation 2 : $\frac{x+y}{3}+\frac{x-y}{4}=11$

$\frac{4x+4y+3x-3y}{12}=11$

$\frac{7x-y}{12}=11$

$7x-y=11 \times 12$

$7x-y=132$-------B

Add A and B

$5x+y+7x-y=48+132$

$5x+7x=48+132$

$12x=180$

$x=\frac{180}{12}$

$x=15$

Substitute the value of x in A

$5(15)+y=48$

$y=-27$

(x,y)=(15,-27)

Hence the solution is (15,-27)