Question

X+y/2 - x-y/3=8, x+y/3+x-y/4=11
Solve by elimination method..

Answer 1

Answer:-

Equation 1 : \frac{x+y}{2}-\frac{x-y}{3}=8

\frac{3x+3y+2x-2y}{6}=8

\frac{5x+y}{6}=8

5x+y=48--------A

Equation 2 : \frac{x+y}{3}+\frac{x-y}{4}=11

\frac{4x+4y+3x-3y}{12}=11

\frac{7x-y}{12}=11

7x-y=11 \times 12

7x-y=132-------B

Add A and B

5x+y+7x-y=48+132

5x+7x=48+132

12x=180

x=\frac{180}{12}

x=15

Substitute the value of x in A

5(15)+y=48

y=-27

(x,y)=(15,-27)