Question

x-y+2z=1
2y-3z=1
3x-2y+4z=2

Answer 1

(1)×3=>3x-3y+6z=3-------(4)
(4)-(3)=>-y+2z=1-----(5)
(5)×2=>-2y+4z=2----(6)
(6)+(2)=>z=3
(6)=>-2y+12=2
=>-2y=-10
=>y=5
(1)=>x-5+6=1
=>x=0
so x=0
y=5
z=3