X-y+2z= 10
2x+y-2z=-4
3x+y+z=7
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The given system is x + 2y + z = 7, 2x – y + 2z = 4, x + y – 2z = -1 Here ∆ = ∣∣∣∣1212−1112−2∣∣∣∣|1212−1211−2| = 1(2 – 2) -2(4 – 2) + 1(2 + 1) = 12 + 3 = 15 ≠ 0 We can apply Cramer’s ruleand the system is consistent and it has unique solution. Read more on Sarthaks.com - https://www.sarthaks.com/865220/solve-the-equations-x-2y-z-7-2x-y-2z-4-x-y-2z-1-by-using-cramers-rule
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